1806 United States House of Representatives election in Delaware

1806 United States House of Representatives election in Delaware

← 1805 (special) October 7, 1806 (1806-10-07) 1807 (special) →
 
Candidate James M. Broom Thomas Fitzgerald
Party Federalist Democratic-Republican
Popular vote 2,353 830
Percentage 60.52% 21.35%

 
Candidate Joseph Haslet Thomas Montgomery
Party Democratic-Republican Democratic-Republican
Popular vote 382 323
Percentage 9.83% 8.31%

U.S. representative before election

James M. Broom
Federalist

Elected U.S. representative

James M. Broom
Federalist

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The 1806 United States House of Representatives election in Delaware was held on October 7, 1806, to elect the U.S. representative from Delaware's at-large congressional district. Incumbent Federalist James M. Broom faced re-election to a full term after winning the previous year's special election. He was challenged by three Democratic-Republicans.

Broom was re-elected with over 60% of the vote, with neither opponent coming close to unseating him.

Results

1806 United States House of Representatives election in Delaware[1]
Party Candidate Votes %
Federalist James M. Broom (incumbent) 2,353 60.52
Democratic-Republican Thomas Fitzgerald 830 21.35
Democratic-Republican Joseph Haslet 382 9.83
Democratic-Republican Thomas Montgomery 323 8.31
Majority 1,523 39.17
Total votes 3,888 100.00
Federalist hold

Results by county

County Broom# Broom% Fitzgerald# Fitzgerald% Haslet# Haslet% Montgomery# Montgomery% Total
Kent 709 95.94% 30 4.06% 739
New Castle 928 43.36% 830 38.79% 382 17.85% 2,140
Sussex 719 71.05% 293 28.95% 1,012

References

  1. ^ "Our Campaigns - DE District At Large Race - Oct 07, 1806". Our Campaigns. January 10, 2006.

See also

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