1810 Delaware gubernatorial election

1810 Delaware gubernatorial election

← 1807 October 2, 1810 1813 →

Nominee Joseph Haslet Daniel Rodney Party Democratic-Republican Federalist Popular vote 3,664 3,593 Percentage 50.49% 49.51%

Governor before election George Truitt Federalist Elected Governor Joseph Haslet Democratic-Republican

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v t e

The 1810 Delaware gubernatorial election was held on October 2, 1810.

Incumbent Federalist Governor George Truitt was not eligible for re-election under the Delaware Constitution of 1792.

Democratic-Republican nominee Joseph Haslet defeated Federalist nominee Daniel Rodney with 50.49% of the vote.

General election

Results

1810 Delaware gubernatorial election^[1][2][3][4]

Party		Candidate	Votes	%	±%
	Democratic-Republican	Joseph Haslet	3,664	50.49%
	Federalist	Daniel Rodney	3,593	49.51%
Majority			71	0.98%
Turnout			7,257	100.00%
	Democratic-Republican gain from Federalist		Swing

References

Bibliography

• Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
• Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
• Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.