1819 Georgia gubernatorial election
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← 1817 | 5 November 1819 | 1821 → |
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| | | Nominee | John Clark | George Troup | | Party | Democratic-Republican | Democratic-Republican | Popular vote | 73 | 60 | Percentage | 54.89% | 45.11% | |
Governor before election Matthew Talbot Democratic-Republican | Elected Governor John Clark Democratic-Republican | |
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The 1819 Georgia gubernatorial election was held on 5 November 1819 in order to elect the Governor of Georgia. Democratic-Republican candidate John Clark defeated fellow Democratic-Republican candidate and former United States Senator for Georgia George Troup in a Georgia General Assembly vote.[1]
General election
On election day, 5 November 1819, Democratic-Republican candidate John Clark won the election against his opponent fellow Democratic-Republican candidate George Troup. Clark was sworn in as the 31st Governor of Georgia on 5 November 1819.[2]
Results
References
- ^ "Georgia 1819 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 8 December 2023.
- ^ "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 8 December 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.