1826 Delaware gubernatorial election
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The 1826 Delaware gubernatorial election was held on October 3, 1826. Incumbent Federalist Governor Samuel Paynter was barred from seeking re-election to a second consecutive term. State Senator Charles Polk Jr. ran as the Federalist nominee to succeed Paynter, while 1823 Democratic-Republican nominee David Hazzard once again ran as his party's nominee. Polk ended up defeating Hazzard by a narrow margin, barely holding onto the governorship for the Federalists.[1]
General election
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Federalist | Charles Polk Jr. | 4,333 | 50.55% | -1.21% | |
| Democratic-Republican | David Hazzard | 4,238 | 49.45% | +1.21% | |
| Majority | 95 | 1.11% | -2.43% | ||
| Turnout | 8,571 | 100.00% | |||
| Federalist hold | |||||
References
- ^ Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 180.
- ^ Dubin 2003, p. 27.
Bibliography
- Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
- Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
- Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.
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