1836 United States presidential election in Tennessee
Election in Tennessee
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The 1836 United States presidential election in Tennessee took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
Tennessee voted for Whig candidate Hugh White, a Senator for Tennessee, over Democratic candidate Martin Van Buren. White won Tennessee by a margin of 15.84%.
Results
| 1836 United States presidential election in Tennessee[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Hugh White of Tennessee | John Tyler of Virginia | 36,027 | 57.92% | 15 | 100.00% | ||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 26,170 | 42.08% | 0 | 0.00% | ||
| Total | 62,197 | 100.00% | 15 | 100.00% | ||||
References
- ^ "1836 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved December 23, 2013.
State and district results of the 1836 United States presidential election | ||
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