1846 Iowa gubernatorial election

Iowa gubernatorial election

1846 Iowa gubernatorial election

26 October 1846 1850 →
 
Nominee Ansel Briggs Thomas McKnight
Party Democratic Whig
Popular vote 7,626 7,379
Percentage 50.82% 49.18%

Governor before election

James Clarke (Territorial)
Whig

Elected Governor

Ansel Briggs
Democratic

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The 1846 Iowa gubernatorial election was held on 26 October 1846 in order to elect the first Governor of Iowa upon Iowa acquiring statehood on 28 December 1846. Democratic nominee Ansel Briggs defeated Whig nominee Thomas McKnight.[1]

General election

On election day, 26 October 1846, Democratic nominee Ansel Briggs won the election by a margin of 247 votes against his opponent Whig nominee Thomas McKnight, thereby gaining Democratic control over the new office of Governor. Briggs was sworn in as the 1st Governor of the new state of Iowa on 28 December 1846.[2]

Results

Iowa gubernatorial election, 1846
Party Candidate Votes %
Democratic Ansel Briggs 7,626 50.82
Whig Thomas McKnight 7,379 49.18
Total votes 15,005 100.00
Democratic gain from Whig

References

  1. ^ "Ansel Briggs". National Governors Association. Retrieved July 14, 2023.
  2. ^ "IA Governor". ourcampaigns.com. March 4, 2005. Retrieved July 14, 2023.