1879 Iowa gubernatorial election

1879 Iowa gubernatorial election

← 1877 October 14, 1879 1881 →
 
Nominee John H. Gear Henry H. Trimble Daniel Campbell
Party Republican Democratic Greenback
Popular vote 157,408 85,364 45,674
Percentage 53.94% 29.25% 15.65%

County results
Gear:     30-40%      40-50%     50-60%     60-70%     70-80%      80-90%      >90%
Trimble:     40-50%     50-60%
Campbell:     30-40%     50-60%

Governor before election

John H. Gear
Republican

Elected Governor

John H. Gear
Republican

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The 1879 Iowa gubernatorial election was held on October 14, 1879. Incumbent Republican John H. Gear defeated Democratic nominee Henry H. Trimble with 53.94% of the vote.

General election

Candidates

Major party candidates

  • John H. Gear, Republican
  • Henry H. Trimble, Democratic

Other candidates

  • Daniel Campbell, Greenback
  • David R. Dungan, Prohibition

Results

1879 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican John H. Gear (incumbent) 157,408 53.94%
Democratic Henry H. Trimble 85,364 29.25%
Greenback Daniel Campbell 45,674 15.65%
Prohibition David R. Dungan 3,291 1.13%
Majority 72,044
Turnout
Republican hold Swing

References

  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved September 20, 2020.