1904 United States presidential election in Delaware
Election in Delaware
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 County Results Roosevelt 50-60%
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The 1904 United States presidential election in Delaware took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. They defeated the Democratic nominees, former Chief Judge of New York Court of Appeals Alton B. Parker and his running mate Henry G. Davis. Roosevelt won the state by a margin of 9.94%.
Results
| 1904 United States presidential election in Delaware[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | Theodore Roosevelt (inc.) | 23,705 | 54.05% | 3 | |
| Democratic | Alton B. Parker | 19,347 | 44.11% | 0 | |
| Prohibition | Silas C. Swallow | 607 | 1.38% | 0 | |
| Social Democratic | Eugene V. Debs | 146 | 0.33% | 0 | |
| Populist | Thomas E. Watson | 51 | 0.12% | 0 | |
| Totals | 43,856 | 100.00% | 3 | ||
| Voter turnout | — | ||||
See also
Notes
References
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
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