1912 Iowa gubernatorial election

1912 Iowa gubernatorial election

← 1910 November 5, 1912 1914 →
 
Nominee George W. Clarke Edward G. Dunn John L. Stevens
Party Republican Democratic Progressive
Popular vote 184,150 182,449 71,879
Percentage 39.93% 39.56% 15.59%

Results by county
Clarke:      30–40%      40–50%      50–60%      60–70%
Dunn:      30–40%      40–50%      50–60%      60–70%

Governor before election

Beryl F. Carroll
Republican

Elected Governor

George W. Clarke
Republican

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The 1912 Iowa gubernatorial election was held on November 5, 1912. Republican nominee George W. Clarke defeated Democratic nominee Edward G. Dunn with 39.93% of the vote.

Primary elections

Primary elections were held on June 3, 1912.[1]

Democratic primary

Candidates

Results

Democratic primary results[1]
Party Candidate Votes %
Democratic Edward G. Dunn 31,965 55.72
Democratic John Taylor Hamilton 25,405 44.28
Total votes 57,370 100.00

Republican primary

Candidates

Results

Republican primary results[1]
Party Candidate Votes %
Republican George W. Clarke 89,107 49.17
Republican Perry Greeley Holden 68,801 37.97
Republican A. V. Proudfoot 23,311 12.86
Total votes 181,219 100.00

General election

Candidates

Major party candidates

  • George W. Clarke, Republican
  • Edward G. Dunn, Democratic

Other candidates

  • John L. Stevens, Progressive
  • I. S. McCrillis, Socialist
  • C. Durant Jones, Prohibition

Results

1912 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican George W. Clarke 184,150 39.93%
Democratic Edward G. Dunn 182,449 39.56%
Progressive John L. Stevens 71,879 15.59%
Socialist I. S. McCrillis 14,986 3.25%
Prohibition C. Durant Jones 7,746 1.68%
Majority 1,701
Turnout
Republican hold Swing

References

  1. ^ a b c Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved July 31, 2020.
  2. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 31, 2020.
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