1920 Iowa gubernatorial election

1920 Iowa gubernatorial election

← 1918 November 2, 1920 1922 →
 
Nominee Nathan E. Kendall Clyde L. Herring
Party Republican Democratic
Popular vote 513,118 338,108
Percentage 58.66% 38.65%

Governor before election

William L. Harding
Republican

Elected Governor

Nathan E. Kendall
Republican

Elections in Iowa
U.S. Presidential elections
Presidential caucuses
Democratic
1976
1980
1984
1992
2000
2004
2008
2012
2016
2020
2024
Republican
1980
1996
2000
2008
2012
2016
2020
2024
U.S. Senate elections
U.S. House of Representatives elections
General elections
Gubernatorial elections
Secretary of State elections
Attorney General elections
Senate elections
House of Representatives elections
Territorial Council elections
Ballot measures
Mayoral elections
  • v
  • t
  • e

The 1920 Iowa gubernatorial election was held on November 2, 1920. Republican nominee Nathan E. Kendall defeated Democratic nominee Clyde L. Herring with 58.66% of the vote.

General election

Candidates

Major party candidates

  • Nathan E. Kendall, Republican
  • Clyde L. Herring, Democratic

Other candidates

  • George J. Peck, Socialist
  • Mathis Faber, Farmer–Labor
  • J. Jay Hisel, Socialist Labor

Results

1920 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Nathan E. Kendall 513,118 58.66%
Democratic Clyde L. Herring 338,108 38.65%
Socialist George J. Peck 13,671 1.56%
Farmer–Labor Mathis Faber 9,153 1.05%
Socialist Labor J. Jay Hisel 760 0.09%
Majority 175,010
Turnout
Republican hold Swing

References

  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved June 30, 2020.
  • v
  • t
  • e
(1919←)   1920 United States elections   (→1921)
President
U.S.
Senate
U.S.
House
State
governors
State
legislatures