1998 Dutch Open – Doubles

Tennis tournament held in the Netherlands
Doubles
1998 Dutch Open
Final
ChampionsAustralia Jacco Eltingh
Netherlands Paul Haarhuis[1]
Runners-upSlovakia Dominik Hrbatý
Slovakia Karol Kučera
Score6–3, 6–2
Events
Singles men women
Doubles men women
← 1997 · Dutch Open · 1999 →
1998 tennis event results

The 1998 Dutch Open was an ATP-tournament held in Amsterdam, Netherlands. The tournament was held from August 3 to August 9.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Netherlands Jacco Eltingh / Netherlands Paul Haarhuis (champions)
  2. United Kingdom Neil Broad / South Africa Piet Norval (first round)
  3. Netherlands Tom Kempers / Argentina Daniel Orsanic (first round)
  4. Czech Republic Jiří Novák / Czech Republic David Rikl (first round)

Draw

Key

Finals

First round Quarterfinals Semifinals Final[1]
1 Netherlands J Eltingh
Netherlands P Haarhuis
4 6 6
South Africa C Haggard
United States J Waite
6 3 3 1 Netherlands J Eltingh
Netherlands P Haarhuis
6 3 6
Netherlands J van Lottum
Netherlands D van Scheppingen
7 6 6 Netherlands J van Lottum
Netherlands D van Scheppingen
3 6 3
Czech Republic L Pimek
Czech Republic T Anzari
6 7 4 1 Netherlands J Eltingh
Netherlands P Haarhuis
6 3 6
Sweden F Bergh
Czech Republic P Vízner
6 6 6 Sweden F Bergh
Czech Republic P Vízner
3 6 3
3 Netherlands T Kempers
Argentina D Orsanic
4 7 3 Sweden F Bergh
Czech Republic P Vízner
6 3 6
Argentina M Hood
Belgium T Vanhoudt
7 6 Argentina M Hood
Belgium T Vanhoudt
1 6 2
Netherlands S Noteboom
Argentina M Puerta
6 1 1 Netherlands J Eltingh
Netherlands P Haarhuis
6 6
Czech Republic C Doseděl
Russia A Olhovskiy
4 7 6 Slovakia D Hrbatý
Slovakia K Kučera
3 2
South Africa M Barnard
South Africa B Barnard
6 6 1 Czech Republic C Doseděl
Russia A Olhovskiy
w/o
Hungary G Köves
South Africa P Rosner
6 4 7 Hungary G Köves
South Africa P Rosner
4 Czech Republic J Novák
Czech Republic D Rikl
2 6 6 Czech Republic C Doseděl
Russia A Olhovskiy
6 3 4
Socialist Federal Republic of Yugoslavia N Djordjevic
Australia J Holmes
7 6 6 Slovakia D Hrbatý
Slovakia K Kučera
2 6 6
Argentina P Albano
Brazil F Meligeni
6 7 1 Socialist Federal Republic of Yugoslavia N Djordjevic
Australia J Holmes
5 7 2
Slovakia D Hrbatý
Slovakia K Kučera
5 6 6 Slovakia D Hrbatý
Slovakia K Kučera
7 6 6
2 United Kingdom N Broad
South Africa P Norval
7 4 3

References

  1. ^ a b "1998 Amsterdam". International Tennis Federation. Archived from the original on 1 January 2015. Retrieved 1 January 2015.
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1998 ATP Tour
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Grand Slam events
Mercedes Super 9
ATP Championship Series
ATP World Series
Team events
  • ATP Tour World Championships, Hanover (singles), Hartford (doubles) (SD)
  • Compaq Grand Slam Cup, Munich (S)