1998 Romanian Open

Tennis tournament
1998 Romanian Open
Date14–21 September
Edition6th
CategoryWorld Series
Draw32S / 16D
Prize money$475,000
SurfaceClay / outdoor
LocationBucharest, Romania
Champions
Singles
Spain Francisco Clavet[1]
Doubles
Romania Andrei Pavel / Romania Gabriel Trifu[2]
← 1997 · Romanian Open · 1999 →

The 1998 Romanian Open was a men's tennis tournament played on Clay in Bucharest, Romania that was part of the World Series of the 1998 ATP Tour. It was the sixth edition of the tournament and was held from 14 September until 21 September 1997. First-seeded Francisco Clavet won the singles title.

Finals

Singles

Spain Francisco Clavet defeated France Arnaud Di Pasquale, 6–4, 2–6, 7–5

  • It was Clevet's 1st singles title of the year and the 6th of his career.

Doubles

Romania Andrei Pavel / Romania Gabriel Trifu defeated Romania George Cosac / Romania Dinu Pescariu, 7–6, 7–6

References

  1. ^ "1998 Bucharest – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1998 Bucharest – Doubles draw". Association of Tennis Professionals (ATP).

External links

  • ITF tournament edition details
  • v
  • t
  • e
1998 ATP Tour
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1999 »
Grand Slam events
Mercedes Super 9
ATP Championship Series
ATP World Series
Team events
  • ATP Tour World Championships, Hanover (singles), Hartford (doubles) (SD)
  • Compaq Grand Slam Cup, Munich (S)