1999 Hall of Fame Tennis Championships – Doubles

Doubles
1999 Hall of Fame Tennis Championships
Final
Champions	Wayne Arthurs Leander Paes
Runners-up	Sargis Sargsian Chris Woodruff
Score	6–7(6–8), 7–6(9–7), 6–3
Events
Singles Doubles
← 1998 · Hall of Fame Open · 2000 →

Doug Flach and Sandon Stolle were the defending champions, but competed this year with different partners. Flach teamed up with Mark Merklein and lost in the first round to David DiLucia and Laurence Tieleman, while Stolle teamed up with Max Mirnyi and lost in the first round to Wayne Ferreira and Nenad Zimonjić.

Wayne Arthurs and Leander Paes won the title by defeating Sargis Sargsian and Chris Woodruff 6–7^(6–8), 7–6^(9–7), 6–3 in the final.^[1]

Seeds

Draw

Key

Draw

	First round							Quarterfinals							Semifinals							Final
	1	W Arthurs L Paes	6	6
		T Ketola R Wassen	2	2				1	W Arthurs L Paes	64	77	7
		S Humphries E Ran	5	4				Q	M Navarra S Pescosolido	77	63	5
	Q	M Navarra S Pescosolido	7	6											1	W Arthurs L Paes	6	4	6
	3	M Mirnyi S Stolle	4	64												D DiLucia L Tieleman	3	6	3
		W Ferreira N Zimonjić	6	77					W Ferreira N Zimonjić
		D Flach M Merklein	64	62					D DiLucia L Tieleman	w/o
		D DiLucia L Tieleman	77	77																		1	W Arthurs L Paes	66	79	6
	WC	M Arnold T Blake	63	77	4																	WC	S Sargsian C Woodruff	78	67	3
		J Thomas D Wheaton	77	64	6				J Thomas D Wheaton	64	4
	WC	S Sargsian C Woodruff	7	6				WC	S Sargsian C Woodruff	77	6
	4	M Barnard B Haygarth	5	4											WC	S Sargsian C Woodruff	6	65	7
		T Shimada C Tontz	64	3												N Godwin M Hill	2	77	5
		N Godwin M Hill	77	6					N Godwin M Hill	3	6	6
	WC	J Blake G Van Emburgh	62	6	4			2	J Gimelstob S Lareau	6	3	2
	2	J Gimelstob S Lareau	77	3	6

References

External links

• Official results archive (ATP)
• Official results archive (ITF)