2006 Nordea Nordic Light Open – Doubles

Doubles

Final

Champions

Jarmila Gajdošová

Runners-up

Yan Zi

Zheng Jie

Score

0–6, 6–4, 6–2

Details

Draw

16 (1WC/1Q)

Seeds

Events

Doubles

← 2005 ·

Nordic Light Open

· 2007 →

2006 tennis event results

Émilie Loit and Katarina Srebotnik were the defending champions, but none competed this year.

Eva Birnerová and Jarmila Gajdošová won the title by defeating Yan Zi and Zheng Jie 0–6, 6–4, 6–2 in the final.^[1]^[2]

Seeds

First round				Quarterfinals					Semifinals					Final

1	Z Yan J Zheng	6	6
	D Klemenschits S Klemenschits	1	2	1	Z Yan J Zheng	6	6
	K Jans A Rosolska	6	7		K Jans A Rosolska	0	0
Q	S Cîrstea J Larsson	1	5						1	Z Yan J Zheng	6	6
3	Y Fedak A Yakimova	3	4							S Cohen-Aloro S Sfar	3	2
	S Cohen-Aloro S Sfar	6	6		S Cohen-Aloro S Sfar	6	4	6
	K Barrois A Radwańska	6	6		K Barrois A Radwańska	2	6	1
	Z Gubacsi A Klepač	1	0											1	Z Yan J Zheng	6	4	2
	N Li A Molik	4	5												E Birnerová J Gajdošová	0	6	6
	E Birnerová J Gajdošová	6	7		E Birnerová J Gajdošová	6	3	6
	S Arvidsson M Müller	6³	2	4	G Navrátilová V Uhlířová	2	6	3
4	G Navrátilová V Uhlířová	7⁷	6							E Birnerová J Gajdošová	5	6	6
WC	E Laine C Wozniacki	6	6						2	E Daniilidou J Wöhr	7	3	1
	M Andersson N Roma	4	1	WC	E Laine C Wozniacki	4	0
	Y Beygelzimer E Bychkova	4	1	2	E Daniilidou J Wöhr	6	6
2	E Daniilidou J Wöhr	6	6

^ "Zheng upsets Myskina in Stockholm". Raidió Teilifís Éireann. 13 August 2006. Retrieved 3 August 2019. Zheng, 23, won this year's Australian Open and Wimbledon women's doubles and was also in the doubles final in Stockholm with compatriot Yan Zi against Czech Eva Birnerova and her Slovak partner Jarmila Gajdosova.
^ "Tennis: Zheng Jie Takes Crown in Stockholm". China.org. 14 August 2006. Retrieved 3 August 2019. However, along with compatriot Yan Zi, Zheng lost the doubles final against Jarmila Gajdosova and Eva Birnerova. The Chinese duo won the first set easily 6-0 but then the Czechoslovakian duo turned on the style. The following sets went 6-4, 6-2 to Gajdosova and Birnerova.