2007 ASB Classic – Singles

Singles
2007 ASB Classic
Final
Champion	Jelena Janković
Runner-up	Vera Zvonareva
Score	7–6(11–9), 5–7, 6–3
Details
Draw	32
Seeds	8
Events
Singles Doubles
← 2006 · ASB Classic · 2008 →

Marion Bartoli was the defending champion, but lost in the second round against Émilie Loit.

Jelena Janković won the title, beating Vera Zvonareva 7–6^(11–9), 5–7, 6–3 in the final.^[1][2][3]

Draw

Seeds

Key

Finals

	Semifinals							Final
	1	Jelena Janković	3
		Camille Pin	0r
								1	Jelena Janković	7	5	6
								5	Vera Zvonareva	69	7	3
	5	Vera Zvonareva	6	7
		Jill Craybas	3	5

Top half

	First round							Second round							Quarterfinals							Semifinals
	1	J Janković	6	6
		J Schruff	3	4				1	J Janković	6	6
	LL	M Johansson	64	1					E Laine	2	1
		E Laine	7	6											1	J Janković	6	6
	WC	M Erakovic	6	4	7										7	E Daniilidou	3	4
	Q	M Tu	3	6	5			WC	M Erakovic	4	6	4
		J Kostanić	3	6	1			7	E Daniilidou	6	4	6
	7	E Daniilidou	6	4	6																	1	J Janković	3
	4	M Bartoli	7	6																			C Pin	0r
		A Morita	64	3				4	M Bartoli	5	4
		E Birnerová	1	1					É Loit	7	6
		É Loit	6	6												É Loit	3	3
	Q	Y Meusburger	7	6												C Pin	6	6
		E Bychkova	5	0				Q	Y Meusburger	6	3	3
		C Pin	6	5	6				C Pin	2	6	6
	8	S Perry	3	7	2

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	5	V Zvonareva	5	6	6
	Q	L Osterloh	7	2	3			5	V Zvonareva	6	6
		R Oprandi	3	4					L Granville	3	4
		L Granville	6	6											5	V Zvonareva	7	2
	Q	V Razzano	7	6											Q	V Razzano	5	0r
		K Kanepi	61	1				Q	V Razzano	6	7
		D Cibulková	1	6	2			3	D Hantuchová	1	5
	3	D Hantuchová	6	3	6																	5	V Zvonareva	6	7
	6	M Müller	6	1	1																		J Craybas	3	5
		P Suárez	3	6	6				P Suárez	7	6
	WC	L Baker	1	1					T Sun	5	4
		T Sun	6	6												P Suárez	3	64
		J Craybas	7	6												J Craybas	6	7
		A Nakamura	5	2					J Craybas	6	7
		G Dulko	6	64	6				G Dulko	3	5
	2	A Myskina	1	7	2

References

External links

• WTA tournament draws