2018 Rogers Cup – Women's doubles

Women's doubles
2018 Rogers Cup
Final
ChampionsAustralia Ashleigh Barty
Netherlands Demi Schuurs
Runners-upChinese Taipei Latisha Chan
Russia Ekaterina Makarova
Score4–6, 6–3, [10–8]
Events
Singles men women
Doubles men women
← 2017 · Rogers Cup · 2019 →
2018 tennis event results

Ekaterina Makarova and Elena Vesnina were the two-time defending champions, but Vesnina chose not to participate this year.

Ashleigh Barty and Demi Schuurs won the title, defeating Makarova and Latisha Chan in the final, 4–6, 6–3, [10–8].

By reaching the final with Makarova, Chan regained the WTA no. 1 doubles ranking at the end of the tournament. Tímea Babos and Kateřina Siniaková were also in contention for the top ranking at the start of the tournament.

Seeds

The top four seeds received byes into the second round.

Draw

Key

Finals

Semifinals Final
          
8 Australia Ashleigh Barty
Netherlands Demi Schuurs
7 6
7 United States Nicole Melichar
Czech Republic Květa Peschke
5 3
8 Australia Ashleigh Barty
Netherlands Demi Schuurs
4 6 [10]
2 Chinese Taipei Latisha Chan
Russia Ekaterina Makarova
6 3 [8]
6 Slovenia Andreja Klepač
Spain María José Martínez Sánchez
4 63
2 Chinese Taipei Latisha Chan
Russia Ekaterina Makarova
6 77

Top half

First round Second round Quarterfinals Semifinals
1 Czech Republic B Krejčíková
Czech Republic K Siniaková
6 66 [8]
Japan S Aoyama
Belarus L Marozava
w/o Japan S Aoyama
Belarus L Marozava
4 78 [10]
Romania M Buzărnescu
Romania M Niculescu
Japan S Aoyama
Belarus L Marozava
2 4
United States R Atawo
Germany A-L Grönefeld
7 4 [4] 8 Australia A Barty
Netherlands D Schuurs
6 6
Ukraine L Kichenok
Latvia J Ostapenko
5 6 [10] Ukraine L Kichenok
Latvia J Ostapenko
3 4
United States B Mattek-Sands
Czech Republic L Šafářová
2 5 8 Australia A Barty
Netherlands D Schuurs
6 6
8 Australia A Barty
Netherlands D Schuurs
6 7 8 Australia A Barty
Netherlands D Schuurs
7 6
7 United States N Melichar
Czech Republic K Peschke
5 3
3 Hungary T Babos
France K Mladenovic
w/o
Chinese Taipei H-c Chan
China Z Yang
6 6 Chinese Taipei H-c Chan
China Z Yang
WC Canada F Abanda
Germany T Maria
4 4 3 Hungary T Babos
France K Mladenovic
6 3 [6]
Latvia A Sevastova
Ukraine E Svitolina
0 4 7 United States N Melichar
Czech Republic K Peschke
2 6 [10]
Germany J Görges
Czech Republic Ka Plíšková
6 6 Germany J Görges
Czech Republic Ka Plíšková
Slovenia D Jakupović
Czech Republic R Voráčová
6 2 [5] 7 United States N Melichar
Czech Republic K Peschke
w/o
7 United States N Melichar
Czech Republic K Peschke
2 6 [10]

Bottom half

First round Second round Quarterfinals Semifinals
6 Slovenia A Klepač
Spain MJ Martínez Sánchez
6 6
Poland A Rosolska
United States A Spears
1 4 6 Slovenia A Klepač
Spain MJ Martínez Sánchez
w/o
Romania I-C Begu
Romania S Halep
6 61 [9] United Kingdom J Konta
China S Zhang
United Kingdom J Konta
China S Zhang
4 77 [11] 6 Slovenia A Klepač
Spain MJ Martínez Sánchez
6 5 [10]
Netherlands K Bertens
Slovenia K Srebotnik
7 6 Netherlands K Bertens
Slovenia K Srebotnik
3 7 [8]
Russia A Pavlyuchenkova
Belarus A Sabalenka
5 3 Netherlands K Bertens
Slovenia K Srebotnik
6 77
4 Czech Republic A Sestini Hlaváčková
Czech Republic B Strýcová
3 63
6 Slovenia A Klepač
Spain MJ Martínez Sánchez
4 63
5 Canada G Dabrowski
China Y Xu
4 6 [6] 2 Chinese Taipei L Chan
Russia E Makarova
6 77
WC Canada E Bouchard
United States S Stephens
6 4 [10] WC Canada E Bouchard
United States S Stephens
6 6
Belgium K Flipkens
Australia D Gavrilova
6 6 Belgium K Flipkens
Australia D Gavrilova
0 4
WC Canada C Branstine
Canada R Marino
1 4 WC Canada E Bouchard
United States S Stephens
4 2
Japan M Kato
Japan M Ninomiya
7 4 [10] 2 Chinese Taipei L Chan
Russia E Makarova
6 6
Ukraine N Kichenok
Australia An Rodionova
5 6 [7] Japan M Kato
Japan M Ninomiya
1 3
2 Chinese Taipei L Chan
Russia E Makarova
6 6

References

  • Main Draw
  • v
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  • e
2018 WTA Tour
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Grand Slam events
WTA Premier Mandatory tournaments
WTA Premier 5 tournaments
WTA Premier tournaments
WTA International tournaments
Team events
  • WTA Finals, Singapore (SD)
  • WTA Elite Trophy, Zhuhai (SD)