Sękowice, Lubusz Voivodeship
Village in Lubusz Voivodeship, Poland
51°55′N 14°43′E / 51.917°N 14.717°E / 51.917; 14.717
PolandSękowice [sɛnkɔˈvit͡sɛ] is a village in the administrative district of Gmina Gubin, within Krosno Odrzańskie County, Lubusz Voivodeship, in western Poland, close to the German border.[1] It lies approximately 4 kilometres (2 mi) south of Gubin, 30 km (19 mi) south-west of Krosno Odrzańskie, and 55 km (34 mi) west of Zielona Góra.
References
- ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.
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Gmina Gubin
Seat (not part of the gmina): Gubin
- Bieżyce
- Brzozów
- Budoradz
- Chęciny
- Chlebowo
- Chociejów
- Czarnowice
- Dobre
- Dobrzyń
- Drzeńsk Mały
- Drzeńsk Wielki
- Dzikowo
- Gębice
- Grabice
- Grochów
- Gubinek
- Jaromirowice
- Jazów
- Kaniów
- Komorów
- Koperno
- Kosarzyn
- Kozów
- Kujawa
- Łazy
- Łomy
- Luboszyce
- Markosice
- Mielno
- Nowa Wioska
- Pleśno
- Polanowice
- Pole
- Późna
- Przyborowice
- Sadzarzewice
- Sękowice
- Sieńsk
- Stargard Gubiński
- Starosiedle
- Strzegów
- Wałowice
- Węgliny
- Wielotów
- Witaszkowo
- Zawada
- Żenichów
- Żytowań
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