1816 United States presidential election in Ohio

Election in Ohio

1816 United States presidential election in Ohio

← 1812 November 1 – December 4, 1816 1820 →
 
Nominee James Monroe Rufus King
Party Democratic-Republican Federalist
Home state Virginia New York
Running mate Daniel D. Tompkins John E. Howard
Electoral vote 8 0
Popular vote 3,326 593
Percentage 84.87% 15.13%

President before election

James Madison
Democratic-Republican

Elected President

James Monroe
Democratic-Republican

Elections in Ohio
U.S. President
U.S. Senate
U.S. House of Representatives
General elections
Gubernatorial elections
Lieutenant Governor elections
Secretary of State elections
Attorney General elections
State Auditor elections
State Treasurer elections
State Supreme Court elections
State House elections
State Senate elections
Mayoral elections
City Council elections
  • v
  • t
  • e

The 1816 United States presidential election in Ohio took place between November 1 and December 4, 1816, as part of the 1816 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio elected Democratic-Republican candidate James Monroe over Federalist candidate Rufus King. Monroe won Ohio by a margin of 69.74%.

Results

1816 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Monroe 3,326 84.87% 8
Federalist Rufus King 593 15.13% 0
Totals 3,919 100.0% 8

See also

References

  1. ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved December 8, 2019.


Stub icon 1 Stub icon 2

This Ohio elections-related article is a stub. You can help Wikipedia by expanding it.

  • v
  • t
  • e