Election in New Jersey
1828 United States presidential election in New Jersey
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← 1824 | October 31 – December 2, 1828 | 1832 → |
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| | | Nominee | John Quincy Adams | Andrew Jackson | | Party | National Republican | Democratic | Home state | Massachusetts | Tennessee | Running mate | Richard Rush | John C. Calhoun | Electoral vote | 8 | 0 | Popular vote | 23,753 | 21,809 | Percentage | 52.12% | 47.86% | |
County Results Adams 50-60% 60-70% 70–80% | Jackson 50-60% 60-70% 70-80% | |
President before election John Quincy Adams National Republican | Elected President Andrew Jackson Democratic | |
The 1828 United States presidential election in New Jersey took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
New Jersey voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Jersey by a narrow margin of 4.26%.
Results
See also
References
- ^ "1828 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved February 28, 2013.
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