1856 United States presidential election in Texas
Election in Texas
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The 1856 United States presidential election in Texas was held on Tuesday November 4, as part of the 1856 United States presidential election. State voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.
Texas voted for the Democratic nominee James Buchanan, who received 67% of the vote. Texas was Buchanan's second-strongest state.
Republican Party nominee John C. Frémont was not on the ballot. Texas would never be won by a Republican candidate until Herbert Hoover narrowly won the state in 1928.[1]
Results
| 1856 United States presidential election in Texas[2] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | James Buchanan | 31,169 | 66.589% | 4 | |
| Know-Nothing | Millard Fillmore | 15,639 | 33.411% | 0 | |
| Total | 46,808 | 100.0% | 4 | ||
See also
References
State results of the 1856 U.S. presidential election | ||
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