1892 United States presidential election in Illinois
Election in Illinois
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 County Results
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The 1892 United States presidential election in Illinois took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.
Illinois was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. This marked the first time a Democratic candidate won Illinois since 1856 when James Buchanan carried the state. This makes Illinois one of three states (along with California and Wisconsin) that Cleveland lost in his first two electoral bids but won in his third.
Results
| 1892 United States presidential election in Illinois[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Grover Cleveland | 426,281 | 48.79% | 24 | |
| Republican | Benjamin Harrison (incumbent) | 399,288 | 45.70% | 0 | |
| Prohibition | John Bidwell | 25,871 | 2.96% | 0 | |
| Populist | James B. Weaver | 22,207 | 2.54% | 0 | |
| Totals | 873,647 | 100.00% | 24 | ||
| Voter turnout | — | ||||
See also
Notes
References
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Illinois
State and district results of the 1892 United States presidential election | ||
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