Hobart Township, Lake County, Indiana

Township in Indiana, United States

41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W / 41.54667; -87.26472CountryUnited StatesStateIndianaCountyLakeGovernment

• TypeIndiana townshipArea

• Total25.98 sq mi (67.3 km²) • Land25.47 sq mi (66.0 km²) • Water0.51 sq mi (1.3 km²)Elevation

^[1]

627 ft (191 m)Population

(2020)^[2]

• Total40,652 • Density1,547.4/sq mi (597.5/km²)FIPS code18-34132^[3]GNIS feature ID453414

Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.^[4]

Historical population
Census	Pop.	%±
1890	2,197	—
1900	2,718	23.7%
1910	3,729	37.2%
1920	5,621	50.7%
1930	9,135	62.5%
1940	12,472	36.5%
1950	21,871	75.4%
1960	39,223	79.3%
1970	40,825	4.1%
1980	42,548	4.2%
1990	38,942	−8.5%
2000	39,636	1.8%
2010	39,417	−0.6%
2020	40,652	3.1%
Source: US Decennial Census^[5]

Geography

According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km²), of which 25.47 square miles (66.0 km²) (or 98.04%) is land and 0.51 square miles (1.3 km²) (or 1.96%) is water.^[4]

References

^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
^ "Census Bureau profile: Hobart Township, Lake County, Indiana". United States Census Bureau. May 2023. Retrieved March 15, 2024.
^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
^ ^a ^b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
^ "Township Census Counts: STATS Indiana".