Zaklopac

Village in Croatia

Zaklopac (Serbian Cyrillic: Заклопац)^[1] is a village in Croatia.

Population

According to the 2011 census, Zaklopac had 23 inhabitants.^[4]

Population^[5]
1857	1869	1880	1890	1900	1910	1921	1931	1948	1953	1961	1971	1981	1991	2001	2011
316	356	292	392	530	544	515	533	262	237	176	156	145	76	15	23

Note: From 1890-1948 it include data for the former settlements of Donji Zaklopac and Gornji Zaklopac.

According to the 1991 census, settlement of Zaklopac had 76 inhabitants, which were ethnically declared as all Serbs.

According to the 1910 census, settlement of Zaklopac had 544 inhabitants in 3 hamlets, which were linguistically and religiously declared as this:

[1] Savezni zavod za statistiku i evidenciju FNRJ i SFRJ, popis stanovništva 1948, 1953, 1961, 1971, 1981. i 1991. godine.
Book: "Narodnosni i vjerski sastav stanovništva Hrvatske, 1880-1991: po naseljima, author: Jakov Gelo, izdavač: Državni zavod za statistiku Republike Hrvatske, 1998., ISBN 953-6667-07-X, ISBN 978-953-6667-07-9;

^ ^a ^b Government of Croatia (October 2013). "Peto izvješće Republike Hrvatske o primjeni Europske povelje o regionalnim ili manjinskim jezicima" (PDF) (in Croatian). Council of Europe. p. 36. Retrieved 30 November 2016.
^ Register of spatial units of the State Geodetic Administration of the Republic of Croatia. Wikidata Q119585703.
^ "Population by Age and Sex, by Settlements" (xlsx). Census of Population, Households and Dwellings in 2021. Zagreb: Croatian Bureau of Statistics. 2022.
^ "Population by Age and Sex, by Settlements, 2011 Census: Zaklopac". Census of Population, Households and Dwellings 2011. Zagreb: Croatian Bureau of Statistics. December 2012.
^ - Republika Hrvatska - Državni zavod za statistiku: Naselja i stanovništvo Republike Hrvatske 1857.-2001.