1872 United States presidential election in Delaware

Election in Delaware

1872 United States presidential election in Delaware

← 1868 November 5, 1872 1876 →
 
Nominee Ulysses S. Grant Horace Greeley
Party Republican Liberal Republican
Home state Illinois New York
Running mate Henry Wilson Benjamin G. Brown
Electoral vote 3 0
Popular vote 11,129 10,205
Percentage 51.00% 46.76%

County Results

Grant

  40-50%
  50-60%

Greeley

  50-60%


President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

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The 1872 United States presidential election in Delaware took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware voted for the Republican candidate, Ulysses S. Grant, over Liberal Republican candidate Horace Greeley. Grant won Delaware by a narrow margin of 4.24%, making him the first Republican to win the state in a presidential election. It would not be carried by another Republican presidential candidate until 1896.

Results

1872 United States presidential election in Delaware[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Henry Wilson of Massachusetts 11,129 51.00% 3 100.00%
Liberal Republican Horace Greely of New York Benjamin Gratz Brown of Missouri 10,205 46.76% 0 0.00%
Straight-Out Democratic Charles O'Conor John Quincy Adams II 488 2.24% 0 0.00%
Total 21,822 100.00% 3 100.00%

See also

References

  1. ^ "1872 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved March 6, 2018.
  2. ^ "1872 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.
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