1908 United States presidential election in Delaware

1908 United States presidential election in Delaware

← 1904 November 3, 1908 1912 →

Nominee William Howard Taft William Jennings Bryan Party Republican Democratic Home state Ohio Nebraska Running mate James S. Sherman John W. Kern Electoral vote 3 0 Popular vote 25,014 22,055 Percentage 52.10% 45.94%

County Results Taft   40-50%   50-60%

President before election Theodore Roosevelt Republican Elected President William Howard Taft Republican

Elections in Delaware
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Wilmington Mayoral elections 2012 2016 2020 2024
v t e

The 1908 United States presidential election in Delaware took place on November 3, 1908. All contemporary 46 states were part of the 1908 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, former Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate John W. Kern. Taft won the state by a margin of 6.16%.

Bryan had previously lost Delaware to William McKinley in both 1896 and 1900.

Results

Results by county

See also

• United States presidential elections in Delaware

Notes

References