1836 United States presidential election in Delaware
Election in Delaware
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 County Results
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The 1836 United States presidential election in Delaware took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Delaware voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Delaware by a margin of 6.54%.
Results
| 1836 United States presidential election in Delaware[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Whig | William Henry Harrison | 4,736 | 53.24% | 3 | |
| Democratic | Martin Van Buren | 4,154 | 46.70% | 0 | |
| N/A | Other | 5 | 0.06% | 0 | |
| Totals | 8,895 | 100.00% | 3 | ||
Results by county
| County | William Henry Harrison Whig | Martin Van Buren Democratic | Various candidates Other parties | Margin | Total votes cast | ||||
| # | % | # | % | # | % | # | % | ||
| Kent | 1,205 | 53.70% | 1,039 | 46.30% | 0 | 0.00% | 166 | 7.40% | 2,244 |
| New Castle | 1,673 | 47.91% | 1,814 | 51.95% | 5 | 0.14% | -141 | -4.04% | 3,492 |
| Sussex | 1,858 | 58.82% | 1,301 | 41.18% | 0 | 0.00% | 557 | 17.63% | 3,159 |
| Total: | 4,736 | 53.24% | 4,154 | 46.70% | 5 | 0.06% | 582 | 6.54% | 8,895 |
See also
References
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| Del. Senate | |||||||||
| Del. House | |||||||||
| Governor |
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| U.S. President |
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| U.S. Senate Class 1 | |||||||||
| U.S. Senate Class 2 | |||||||||
| U.S. House |
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